-0.2x^2+2x+45=50

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Solution for -0.2x^2+2x+45=50 equation: 



-0.2x^2+2x+45=50

We move all terms to the left:

-0.2x^2+2x+45-(50)=0

We add all the numbers together, and all the variables

-0.2x^2+2x-5=0

a = -0.2; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·(-0.2)·(-5)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{-0.4}=+5$

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